Which of the following has been arranged in o | vedclass

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(C) To determine the order,calculate the oxidation number $(ON)$ of nitrogen in each species:$NH_4^+$: $x + 4(+1) = +1 \implies x = -3$$N_2H_4$: $2x +

Vedclass · Accepted Answer

$NH_4^+ < N_2H_4 < NH_2OH < N_2O$

Vedclass · Answer

(C) To determine the order,calculate the oxidation number $(ON)$ of nitrogen in each species:$NH_4^+$: $x + 4(+1) = +1 \implies x = -3$$N_2H_4$: $2x + 4(+1) = 0 \implies 2x = -4 \implies x = -2$$NH_2OH$: $x + 2(+1) + (-2) + (+1) = 0 \implies x + 1 = 0 \implies x = -1$$N_2O$: $2x + (-2) = 0 \implies 2x = +2 \implies x = +1$Thus,the increasing order is: $\mathop {NH_4^+}\limits_{(-3)} < \mathop {N_2H_4}\limits_{(-2)} < \mathop {NH_2OH}\limits_{(-1)} < \mathop {N_2O}\limits_{(+1)}$.

List $I$ (Compound)	List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$	$(1)$ $+5$
$(B)$ $HNO$	$(2)$ $-3$
$(C)$ $NH_3$	$(3)$ $+4$
$(D)$ $N_2O_5$	$(4)$ $+1$

Which of the following has been arranged in order of increasing oxidation number of nitrogen?

Similar Questions

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
List $I$ (Compound) List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$ $(1)$ $+5$
$(B)$ $HNO$ $(2)$ $-3$
$(C)$ $NH_3$ $(3)$ $+4$
$(D)$ $N_2O_5$ $(4)$ $+1$

Codes: $A \quad B \quad C \quad D$

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The oxidation number of $P$ in $KH_2PO_2$ is:

Equivalent weight of $KMnO_4$ acting as an oxidant in acidic medium is

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